Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 28 - Physical Optics: Interference and Diffraction - Problems and Conceptual Exercises - Page 1007: 67

Answer

$371.3cm^{-1}$

Work Step by Step

We can calculate the number of lines per centimeter on the grating as follows: $N=\frac{sin\theta}{m\lambda}$ We plug in the known values to obtain: $N=\frac{sin(1.250^{\circ})}{(1)(587.5\times 10^{-9}m)}$ $N=3.713\times 10^{-4}m^{-1}$ $N=3.713\times 10^{-4}(\frac{1}{100cm^{-1}})$ $N=371.3cm^{-1}$
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