Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 28 - Physical Optics: Interference and Diffraction - Problems and Conceptual Exercises - Page 1007: 63

Answer

$2.95^{\circ}, 5.92^{\circ}, 8.90^{\circ}$

Work Step by Step

We can find the required angles as follows: $\theta_1=sin^{-1}(\frac{m\lambda}{d})$ We plug in the known values to obtain: $\theta_1=sin^{-1}[\frac{(1)(655\times 10^{-9}m)}{0.00127\times 10^{-2}m}]$ $\theta_1=2.95^{\circ}$ for $m_2$ $\theta_2=sin^{-1}[\frac{2(655\times 10^{-9}m)}{12700\times 10^{-9}m}]$ $\theta_2=5.92^{\circ}$ for $m=3$ $\theta_3=sin^{-1}[\frac{3(655\times 10^{-9}m)}{12700\times 10^{-9}m}]$ $\theta_3=8.90^{\circ}$
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