Answer
(a) $1.1\times 10^{-5}rad$
(b) $7.04\times 10^{-6}m$
Work Step by Step
(a) We know that
$2\theta=2(1.22)\frac{\lambda}{D}$
We plug in the known values to obtain:
$2\theta=2(1.22)(\frac{540\times 10^{-9}m}{0.12m})$
$\implies 2\theta=1.1\times 10^{-5}rad$
(b) We know that
$2y=2Ltan\theta$
We plug in the known values to obtain:
$2y=2(0.64m)tan(\frac{1.1\times 10^{-5}rad}{2})$
$2y=7.04\times 10^{-6}m$
