Answer
$W=69.888\mu m$
Work Step by Step
We can find the required width of the slit as follows:
$W=\frac{m\lambda L}{y}$
We plug in the known values to obtain:
$W=\frac{1(546nm)(1.60m)}{(1.25cm)}$
$W=69.888\times 10^{-6}m$
$W=69.888\mu m$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 28 - Physical Optics: Interference and Diffraction - Problems and Conceptual Exercises - Page 1006: 46
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