Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 28 - Physical Optics: Interference and Diffraction - Problems and Conceptual Exercises - Page 1006: 42

Answer

$1.0~cm$

Work Step by Step

We know that the length of the bands on the glass plate is given as $a=\frac{0.052\times 10^{-3}m}{2.857\times 10^{-5}m}$ $a=1.82m$ Now, the number of dark bands formed is given as $m=\frac{2d}{\lambda}$ $m=\frac{2(0.052\times 10^{-3}m)}{589\times 10^{-9}m}$ $m=177 dark \space bands$ Now, the distance between the adjacent dark bands can be determined as $t=\frac{1.82m}{177}$ $t=0.0103075m=1.03075cm$
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