Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 26 - Geometrical Optics - Problems and Conceptual Exercises - Page 943: 83

Answer

(a) $34cm$ (b) $-1.2$

Work Step by Step

(a) We know that $\frac{1}{d_{i1}}=\frac{1}{f_1}-\frac{1}{d_{\circ 1}}$ $\implies \frac{1}{d_{i1}}=\frac{1}{14cm}-\frac{1}{24cm}=0.0297$ $\implies d_{i1}=33.6cm$ Similarly $\frac{1}{d_{i2}}=\frac{1}{f_2}-\frac{1}{d_{\circ 2}}$ $\implies \frac{1}{d_{i2}}=\frac{1}{-7.0cm}-\frac{1}{1.40cm}$ $\implies d_{i2}=-1.16cm$ Now $d_i=35cm+d_{i2}$ $\implies d_i=35cm-1.16cm=34cm$ (b) We know that $m_1m_2=(\frac{di_1}{d_{\circ1}})(-\frac{d_{i2}}{d_{\circ2}})$ We plug in the known values to obtain: $m_1m_2=(\frac{33.6cm}{24cm})(\frac{-1.16cm}{1.42cm})=-1.2$
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