Answer
(a) $0.98m$
(b) $68cm$
Work Step by Step
(a) We can find the location of the image as
$d_i=(\frac{1}{f}-\frac{1}{d_{\circ}})^{-1}$
We plug in the known values to obtain:
$d_i=(\frac{1}{35.0}-\frac{1}{36.3})^{-1}$
$d_i=0.98m$
The image is located to the right of the lens.
(b) The height of the image can be determined as
$h_i=-\frac{d_ih_{\circ}}{d_{\circ}}$
We plug in the known values to obtain:
$h_i=-\frac{977(2.54)}{36.3}=-68cm$
The negative sign shows that the image is inverted.
