Answer
$d_i=-15cm$, $m=0.52$
Work Step by Step
We can find the image distance as
$d_i=(\frac{1}{f}-\frac{1}{d_{\circ}})^{-1}$
We plug in the known values to obtain:
$d_i=(\frac{1}{-32}-\frac{1}{29})^{-1}$
$d_i=-15cm$
Now we can find the magnification
$m=-\frac{d_i}{d_{\circ}}$
We plug in the known values to obtain:
$m=-\frac{-15}{29}=0.52$
