Answer
No
Work Step by Step
We know that for an LC circuit, the angle between the current and voltage is $+90^{\circ}$ or $-90^{\circ}$
The power consumed by an LC circuit is given as $P_{avg}=V_{rms}\times I_{rms}\times cos\phi$
$P_{avg}=V_{rms}\times I_{rms}\times cos(\pm 90^{\circ})=0$ because $cos(\pm 90^{\circ})=0$
Thus, an LC circuit consumes zero power.
