Answer
Please see the work below.
Work Step by Step
We know that in an LC circuit the voltage and current are always at a phase difference $\phi=+\pi/2 or -\pi /2$. We also know that at resonance $X_L=X_C$ and given that the frequency is more than the frequency at resonance, therefore $X_L(=\omega L)\gt X_C(=\frac{1}{\omega C})$. Thus, the indicator dominates and we conclude that the voltage leads the current and the required phase angle is $\phi=+\pi/2$ or $90^{\circ}$.
