Answer
$12mH$
Work Step by Step
We know that
$L=\mu_{\circ}A\frac{N^2}{l}$
We plug in the known values to obtain:
$L=\pi(4\pi\times 10^{-7}T.m/A)(\frac{(640)^2}{0.25})(0.043)^2$
$L=12mH$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 23 - Magnetic Flux and Faraday's Law of Induction - Problems and Conceptual Exercises - Page 832: 50
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