Chapter 23 - Magnetic Flux and Faraday's Law of Induction - Problems and Conceptual Exercises - Page 832: 51

$-15.5mV$

We know that $L=\mu_{\circ}n^2lA$ We plug in the known values to obtain: $L=(4\pi\times 10^{-7})(445)^2(0.750)(1.81\times 10^{-3})$ $L=353.2\mu H$ Now we can find emf as $\epsilon=-L\frac{\Delta I}{\Delta t}$ We plug in the known values to obtain: $\epsilon=-(3532\times 10^{-4})(\frac{2.00}{45.5\times 10^{-3}})=-15.5mV$