Chapter 23 - Magnetic Flux and Faraday's Law of Induction - Problems and Conceptual Exercises - Page 829: 16

$\frac{\Delta B}{\Delta t}=4.9\times 10^2\frac{T}{s}$

We know that $\epsilon=IR=(0.32)(110)=35V$ Now $\frac{\Delta B}{Delta t}=\frac{\epsilon}{NA}$ We plug in the known values to obtain: $\frac{\Delta B}{\Delta t}=\frac{35}{(1)(7.2\times 10^{-2})}$ $\frac{\Delta B}{\Delta t}=4.9\times 10^2\frac{T}{s}$