Answer
(a) $-0.1KV $
(b) 0
(c) $0.04KV $
Work Step by Step
(a) We know that
$\epsilon=-N[\frac{\phi_2-\phi_1}{t_2-t_1}]$
We plug in the known values to obtain:
$\epsilon=-[\frac{10Wb-0Wb}{0.1s}]$
$\epsilon=-0.1KV $
(b) We know that at $ t=0.15s $ $\epsilon=0$ because the flux is the same between $0.1s $ and $0.2s $.
(c) As $\epsilon=-N[\frac{\phi_2-\phi_1}{t_2-t_1}]$
We plug in the known values to obtain:
$\epsilon=-(1)[\frac{-5Wb-10Wb}{0.6s-0.2s}]$
$\epsilon=0.04KV $
