Chapter 23 - Magnetic Flux and Faraday's Law of Induction - Problems and Conceptual Exercises - Page 829: 4

$1.7\times 10^{-2}Wb$

Since the horizontal component of the magnetic field is parallel to the floor, the horizontal component has zero magnetic flux and the flux in the vertical component is given as: $\phi=BAcon\theta=BAcos0^{\circ}$ $\phi=(4.2\times 10^{-5})(22)(18)$ $\phi=1.7\times 10^{-2}Wb$