Answer
(a) $9.83\frac{m}{s}$
(b) $13.9s$
Work Step by Step
(a) We know that
$v=\frac{qrB}{m}$
We plug in the known values to obtain:
$v=\frac{(1.25\times 10^{-6})(21.8)(1.01)}{2.80\times 10^{-5}}$
$v=9.83\frac{m}{s}$
(b) We know that
$t=\frac{2\pi m}{qB}$
We plug in the known values to obtain:
$t=\frac{2\pi(21.8)}{9.83}$
$t=13.9s$
