Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 22 - Magnetism - Problems and Conceptual Exercises - Page 793: 36

Answer

a) $F=1.6N$ b) $F=1.54N$

Work Step by Step

(a) We know that $F=ILBsin\theta$ We plug in the known values to obtain: $F=(110)(250)(5.9\times 10^{-5})sin90^{\circ}$ $F=1.6N$ (b) As $F=ILBsin\theta$ We plug in the known values to obtain: $F=(110)(250)(5.9\times 10^{-5})sin72{\circ}$ $F=1.54N$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.