Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 22 - Magnetism - Problems and Conceptual Exercises - Page 793: 34

Answer

Please see the work below.

Work Step by Step

(a) We know that $B=\frac{\frac{F}{L}}{I sin\theta}$ We plug in the known values to obtain: $B=\frac{0.033}{(6.2)sin7.5^{\circ}}=0.041T$ $B=41mT$ (b) As $\theta=sin^{-1}\frac{\frac{F}{L}}{IB}$ We plug in the known values to obtain: $\theta=sin^{-1}\frac{0.015}{(6.2)(0.041)}$ $\theta=3.4^{\circ}$
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