Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 19 - Electric Charges, Forces, and Fields - Problems and Conceptual Exercises - Page 689: 104

Answer

(C) $5.40\times 10^{-7}N$

Work Step by Step

We can find the magnitude of electrostatic force as follows: $F=\frac{Kq_1q_2}{r^2}$ We plug in the known values to obtain: $F=\frac{(8.99\times 10^9)(93.0\times 10^{-12})^2}{(0.0120)^2}$ $F=5.40\times 10^{-7}N$
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