Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 19 - Electric Charges, Forces, and Fields - Problems and Conceptual Exercises - Page 689: 103

Answer

(B) $5.81\times 10^8electrons$

Work Step by Step

We can find the number of electrons as follows: $N=\frac{Q}{e}$ We plug in the known values to obtain: $N=\frac{93.0\times 10^{-12}}{1.6\times 10^{-19}}$ $N=5.81\times 10^8electrons$
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