Answer
(C) $1.02\times 10^{-8}N$
Work Step by Step
We know that
$E=\frac{F}{q}$
This can be rearranged as:
$F=qE$
We plug in the known values to obtain:
$F=(93\times 10^{-12})(110)$
$F=1.02\times 10^{-8}N$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 19 - Electric Charges, Forces, and Fields - Problems and Conceptual Exercises - Page 689: 106
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