Answer
$1.2\times 10^{25}N$
$10^{22}$ times stronger
Work Step by Step
We know that
$N_e=70\times \frac{1mol}{0.018Kg}\times \frac{6.022\times 10^{23}}{mol}\times \frac{10e^{-}}{mol}=2.3\times 10^{28}e^{-}$
and $q=0.010\times(2.3\times 10^{28})(1.6\times 10^{-19})=3.7\times 10^7C$
Now we can find the electrostatic force as
$F=\frac{Kq^2}{r^2}$
We plug in the known values to obtain:
$F=\frac{(8.99\times 10^9)(3.7\times 10^7)^2}{((1.0)^2}=1.2\times 10^{25}N$
Thus, the force is $10^{22}$times stronger than the person's weight.