Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 19 - Electric Charges, Forces, and Fields - Problems and Conceptual Exercises - Page 687: 83

Answer

$1.2\times 10^{25}N$ $10^{22}$ times stronger

Work Step by Step

We know that $N_e=70\times \frac{1mol}{0.018Kg}\times \frac{6.022\times 10^{23}}{mol}\times \frac{10e^{-}}{mol}=2.3\times 10^{28}e^{-}$ and $q=0.010\times(2.3\times 10^{28})(1.6\times 10^{-19})=3.7\times 10^7C$ Now we can find the electrostatic force as $F=\frac{Kq^2}{r^2}$ We plug in the known values to obtain: $F=\frac{(8.99\times 10^9)(3.7\times 10^7)^2}{((1.0)^2}=1.2\times 10^{25}N$ Thus, the force is $10^{22}$times stronger than the person's weight.
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