Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 19 - Electric Charges, Forces, and Fields - Problems and Conceptual Exercises - Page 687: 79

Answer

$N=8.4\times 10^{18}electrons$

Work Step by Step

We can find the number of electrons as $N=\frac{Q}{e}$ $\implies N=\frac{1}{e}(\frac{\Delta Q}{\Delta t}t)$ We plug in the known values to obtain: $N=\frac{1}{1.6\times 10^{-19}}[\frac{0.30}{1.0}(4.5)]$ $N=8.4\times 10^{18}electrons$
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