Answer
$q_1=9q_2$
Work Step by Step
In the given scenario
$F_1=F_2$
$\implies \frac{Kq_1Q}{(\frac{3}{4}d)^2}= \frac{Kq_2Q}{(d-\frac{3}{4}d)^2}$
$\implies \frac{16q_1}{9}=\frac{16q_2}{1}$
$\implies q_1=9q_2$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 19 - Electric Charges, Forces, and Fields - Problems and Conceptual Exercises - Page 685: 41
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