Answer
(b) $1.1\times 10^8J$
Work Step by Step
We know that
$Q=mc\Delta T$
We plug in the known values to obtain:
$Q=(1500Kg)(4.19\times 10^3J/Kg.C^{\circ})(22^{\circ}-4.0^{\circ})$
$Q=1.1\times 10^8J$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 18 - The Laws of Thermodynamics - Problems and Conceptual Exercises - Page 649: 98
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