Answer
$\frac{W}{Q}=0.4$
Work Step by Step
We can find the required ratio $\frac{W}{Q}$ as follows:
$\frac{W}{Q}=\frac{-nR\Delta T}{nC_p\Delta T}$
$\frac{W}{Q}=\frac{-R}{C_p}$
$\implies \frac{W}{Q}=\frac{-R}{\frac{5R}{2}}$
$\implies \frac{W}{Q}=\frac{-2}{5}=0.4$