Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 18 - The Laws of Thermodynamics - Problems and Conceptual Exercises - Page 649: 94

Answer

$\frac{W}{Q}=0.4$

Work Step by Step

We can find the required ratio $\frac{W}{Q}$ as follows: $\frac{W}{Q}=\frac{-nR\Delta T}{nC_p\Delta T}$ $\frac{W}{Q}=\frac{-R}{C_p}$ $\implies \frac{W}{Q}=\frac{-R}{\frac{5R}{2}}$ $\implies \frac{W}{Q}=\frac{-2}{5}=0.4$
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