Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 18 - The Laws of Thermodynamics - Problems and Conceptual Exercises - Page 649: 96

Answer

$COP=\frac{1-e}{e}$

Work Step by Step

We know that the efficiency of the Carnot engine is given as $e=1-\frac{T_c}{T_h}$ Coefficient of the refrigerator is given as $COP=\frac{Q_c}{W}$ $\implies COP=\frac{Q_c}{Q_h-Q_c}$ $COP=\frac{1}{\frac{Q_h}{Q_c}-1}$ $COP=\frac{1}{\frac{T_h}{T_c}-1}$ $COP=\frac{1}{\frac{1}{1-e}-1}$ $COP=\frac{1-e}{e}$
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