Answer
a) 590 J
b) 0.23
Work Step by Step
(a) We know that
$Heat exhausted=Q_h=Q_c+W$
We plug in the known values to obtain:
$Heat\space exhausted= 110+480=590J$
(b) We can find out the coefficient of performance as
$COP=\frac{Q_c}{W}$
We plug in the known values to obtain:
$COP=\frac{110}{480}$
$COP=0.23$
