Answer
(a) $15.0KJ$
(b) $12.3KJ$
(c) decrease
Work Step by Step
(a) We can find the heat taken in from the hot reservoir as follows:
$Q_h=\frac{W}{e}$
We plug in the known values to obtain:
$Q_h=\frac{2700J}{0.18}$
$Q_h=15.0KJ$
(b) The heat given to the cold reservoir can be determined as
$Q_c=Q_h-W$
We plug in the known values to obtain:
$Q_c=15.0KJ-2.7KJ$
$Q_c=12.3KJ$
(c) We know that $Q_h$ and $Q_c$ are inversely proportional to the efficiency of the engine. Hence, if the efficiency of the engine increases then $Q_h$ and $Q_c$ will decrease.
