Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 16 - Temperature and Heat - Problems and Conceptual Exercises - Page 570: 81

Answer

$0.17C^{\circ}$

Work Step by Step

We can find the change in temperature as follows: $Q=mC\Delta T=mgh$ This simplifies to: $\Delta T=\frac{gh}{C}$ We plug in the known values to obtain: $\Delta T=\frac{(9.81)(72)}{4186}$ $\Delta T=0.17C^{\circ}$
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