Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 16 - Temperature and Heat - Problems and Conceptual Exercises - Page 570: 75

Answer

$77.9F^{\circ}$

Work Step by Step

We know that $\frac{C}{5}=\frac{F-32}{9}$ This can be rearranged as: $F=\frac{9C}{5}+32$ We plug in the known values to obtain: $F=\frac{25.48\times 9}{5}+32$ $\implies F=77.9F^{\circ}$
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