Answer
$15.6C^{\circ}$
Work Step by Step
We can find the required temperature as follows:
$T=\frac{mgh+m_rC_rT_r+m_wC_wT_w}{m_rC_r+m_wC_w}$
We plug in the known values to obtain:
$T=\frac{(226)(9.81)(5.25)+(226)(1010)(30.2)+(6.00)(1.00\times 10^3)(4186)(15.5)}{(226)(1010)+(6.00)(1.00\times 10^3)(4186)}$
$T=15.6C^{\circ}$
