Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 15 - Fluids - Problems and Conceptual Exercises - Page 537: 111

Answer

$R=2\sqrt{(d-h)h}$

Work Step by Step

We know that the velocity is given as $v=\sqrt{2g(d-h)}$ The time taken by water stream is given as $t=\sqrt{\frac{2g}{h}}$ Now $R=vt$ $\implies R=(\sqrt{2g(d-h)})(\sqrt{\frac{2h}{g}})$ This simplifies to: $R=2\sqrt{(d-h)h}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.