Answer
$16Kg$
Work Step by Step
We can find the mass of water as follows:
$m_w=\rho_w(0.65V_{box})=\rho_w(0.65L^3)$
We plug in the known values to obtain:
$m_w=(1000)(0.65(0.29m)^3)=16Kg$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 15 - Fluids - Problems and Conceptual Exercises - Page 537: 113
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