Answer
$0.20$
Work Step by Step
We know that
$\rho_{geode}=\frac{2\rho_w}{\rho_{solid}}$
We plug in the known values to obtain:
$\rho_{geode}=\frac{2(1000Kg/m^3)}{2500Kg/m^3}=0.80$
Now $f_{air}=1-f_{solid}$
$\implies f_{air}=1-0.80=0.20$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 15 - Fluids - Problems and Conceptual Exercises - Page 537: 110
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