Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 15 - Fluids - Problems and Conceptual Exercises - Page 534: 72

Answer

$1.92$

Work Step by Step

We know that $\frac{\Delta P_1\pi r_1^4}{8\eta L}=\frac{\Delta P_2\pi r_2^4}{8\eta L}$ This simplifies to: $\frac{\Delta P_2}{\Delta P_1}=\frac{r_1^4}{r_2^4}$ $\implies \frac{\Delta P_2}{\Delta P_1}=\frac{r_1^4}{(0.85r_1)^4}=1.92$
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