Answer
$1.08\times 10^5Pa$
Work Step by Step
We know that
$P_1=P_{atm}+\rho gy_2$
We plug in the known values to obtain:
$P_1=1.01\times 10^5+(1000)(9.81)(0.68)$
$P_1=1.08\times 10^5Pa$
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