Chapter 14 - Waves and Sound - Problems and Conceptual Exercises - Page 497: 112

(a) $14.75m$ (b) $3.30m$

(a) We know that $f=\frac{f_{A-flat}}{2}$ $f=\frac{415.3}{4}=103.8Hz$ Now we can find the wavelength $v=\lambda f$ $\lambda=\frac{v}{f}$ We plug in the known values to obtain: $\lambda=\frac{153}{103.8}=14.75m$ (b) As $v=\lambda f$ $\implies \lambda=\frac{v}{f}$ We plug in the known values to obtain: $\lambda=\frac{343}{103.8}=3.30m$