Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 14 - Waves and Sound - Problems and Conceptual Exercises - Page 497: 115

Answer

$T=\sqrt{\frac{2\pi \lambda}{g}}$

Work Step by Step

We know that $T=\frac{\lambda}{v}$ As given that $v=\sqrt\frac{{g\lambda}}{{2\pi}}$ $\implies T=\frac{\lambda}{\sqrt\frac{{g\lambda}}{{2\pi}}}$ This simplifies to: $T=\sqrt{\frac{2\pi \lambda}{g}}$
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