Chapter 14 - Waves and Sound - Problems and Conceptual Exercises - Page 497: 111

$3.9\times 10^7years$

First of all, we find the frequency $f=\frac{f_{B-flat}}{2^{59}}=(\frac{466.2}{2^{59}})=8.087\times 10^{-16}Hz$ Now we can calculate the time period as $T=\frac{1}{f}=\frac{1}{8.087\times 10^{-16}}=1.237\times 10^{15}s$ We convert this time into years $T=1.237\times 10^{15}(\frac{1yr}{3.16\times 10^7})=3.9\times 10^7years$