Answer
$2.9\times 10^{-9}Hz$
Work Step by Step
The required frequency can be determined as
$f=\frac{1}{T}$
We plug in the known values to obtain:
$f=(\frac{1}{11yr})(\frac{yr}{3.156\times 10^7s})$
$f=2.9\times 10^{-9}Hz$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 13 - Oscillations About Equilibrium - Problems and Conceptual Exercises - Page 449: 78
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