Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 13 - Oscillations About Equilibrium - Problems and Conceptual Exercises - Page 449: 68

Answer

(a) $1.2s$ (b) $0.91\frac{m}{s}$

Work Step by Step

(a) We know that $T=2\pi \sqrt{\frac{2L}{3g}}$ We plug in the known values to obtain: $T=2\pi\sqrt{\frac{2(0.55)}{3(9.81)}}$ $T=1.2s$ (b) The required speed can be determined as $v=\frac{d}{\frac{1}{2}T}$ We plug in the known values to obtain: $v=\frac{0.55}{0.607}=0.91\frac{m}{s}$
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