Chapter 12 - Gravity - Problems and Conceptual Exercises - Page 414: 93

$\frac{GMm}{2r}$

We can find the expression for the kinetic energy of a satellite as follows: $F_{centripetal}=F_{gravity}$ $\implies \frac{mv^2}{r}=\frac{GMm}{r^2}$ $\implies v^2=\frac{GM}{r}$ We know that $K.E=\frac{1}{2}mv^2$ $\implies K.E=\frac{1}{2}m(\frac{GM}{r})$ $K.E=\frac{GMm}{2r}$