Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 12 - Gravity - Problems and Conceptual Exercises - Page 414: 99

Answer

$(D) 8.2h$

Work Step by Step

We can find the time period as $T=\frac{2\pi}{\sqrt{GM_C}}r^{\frac{3}{2}}$ We plug in the known values to obtain: $T=\frac{2\pi}{\sqrt{(6.67\times 10^{-11})(1.1\times 10^{14})}}(5400)^{\frac{3}{2}}$ $T=2.9\times 10^4s=8.2h$
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