Answer
$(B) 2.3\frac{m}{s}$
Work Step by Step
As we know that
$v_e=\sqrt{\frac{2GM_C}{R_C}}$
We plug in the known values to obtain:
$v_e=\sqrt{\frac{2(6.67\times 10^{-11})(1.1\times 10^{14})}{2700}}$
$v_e=2.3\frac{m}{s}$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 12 - Gravity - Problems and Conceptual Exercises - Page 414: 98
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