Answer
$M=1.90\times 10^{27}Kg$
Work Step by Step
The mass of Jupiter can be determined as below
$M=(\frac{2\pi}{T})^2\frac{r^3}{G}$
We plug in the known values to obtain:
$M=(\frac{2\pi}{6.18\times 10^5})^2\frac{(1.07\times 10^9)^3}{6.67\times 10^{-11}}$
$M=1.90\times 10^{27}Kg$
