Answer
$h=2.64\times 10^6m$
Work Step by Step
We know that
$(R_E+h)^2=2R_E^2$
This simplifies to:
$h=\sqrt{2-1}R_E$
We plug in the known values to obtain:
$h=(\sqrt {2}-1)(6.37\times 10^6)$
$h=2.64\times 10^6m$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 12 - Gravity - Problems and Conceptual Exercises - Page 410: 15
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