Answer
$g=0.00270\frac{m}{s^2}$
Work Step by Step
As $g=\frac{GM_E}{r^2}$
We plug in the known values to obtain:
$g=6.67\times 10^{-11}\times \frac{5.97\times 10^{24}}{(3.84\times 10^8)^2}$
$g=0.00270\frac{m}{s^2}$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 12 - Gravity - Problems and Conceptual Exercises - Page 410: 17
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