Answer
$116W$
Work Step by Step
We know that
$\tau=Fr$
$\tau=3.68oz.in\times\frac{1lb}{16oz}\times \frac{4.45}{1lb}\times \frac{1m}{39.4in}$
$\tau=0.0260N.m$
we convert the angular velocity into rad/s as
$\omega=42500\frac{rev}{min}\times \frac{2\pi rad}{rev}\times \frac{1min}{60s}=4450\frac{rad}{s}$
Now we can calculate the power output as
$P=\tau \omega$
We plug in the known values to obtain:
$P=(0.0260)(4450)$
$P=116W$