Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 11 - Rotational Dynamics and Static Equilibrium - Problems and Conceptual Exercises - Page 371: 78

Answer

$0.089N.m$

Work Step by Step

We can find the torque as follows: $\tau=\frac{W}{\Delta \theta}$ We plug in the known values to obtain: $\tau=\frac{0.14}{0.25rev\times 2\pi rad/rev}$ $\tau=0.089N.m$
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